It is: 28+1 = 29
143
They add up to 121
The numbers that multiply to give you 121 and add to give you 8 are 11 and -11. When multiplied, 11 × -11 equals 121; however, they do not add up to 8. The correct numbers that meet both conditions are 11 and -3, as 11 × -3 equals -33, and 11 + (-3) equals 8. Therefore, there are no real numbers that satisfy both conditions simultaneously.
(1) Take the difference of the two previous numbers in sequence (2) Add 4 to this difference. (3) Take the number from step #2 and add it to the previous number in the sequence. For example, to find the next number in the sequence: (1) 121 - 90 = 31 (2) 31 + 4 = 35 (3) 121 + 35 = 156
121 multiplied by 121 is 14,641.
Add 200 to it because 121 plus 200 = 321
sum means add up so 121 + 7 = 128
The number is 55+66 = 121
143
99
They add up to 121
Do you mean? X^2 - 121 = 0 add 121 to each side X^2 = 121 take square root of each side x = (+/-) 11
44 + 77 = 121
-1 and -120
57+64= 121
-121
112 + 32 = 121 + 9 = 130