11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
x2 - 3x + 2 = 0
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
it is 121
x2+3=124 x2=121 x= square root(121) x=11
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
x2 23x equals 0
x: x2 - 81 = 0
If: x2-4 = 0 Then: x = 2
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
x2-10 = 0 x2 = 10 x = the square root of 10