If you mean: (x-4)(x+12) then it is x^2 +8x -48
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
x4+6x3-2x-12 (x3-2)(x+6)
I assume you meant x^4 + 5x^2 +10x + 12. The remainder is 28
sqrt(x4) = x4/2 = x2
N = x4 x8 = x4+4 = (x4)2 = N2
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
x times x times x times x = x4
f'(x) = x^(3) / 3 Hence f(x) = 3x^(2) / 3 +C f(x) = x^(2) + C ' The '3' cancels out. The 'C' is a constant that comes with antoderivation.
I assume the x4 is x to the 4th power, and x2 is x², or x squared. The two factors would be: (x + 2)(x - 2)(x² + 3) There are 4 solutions for x: x = 2 x = -2 x = √-3 x = -√-3
(x2 + y2)(x + y)(x - y) = x4 - y4.
x4+6x3-2x-12 (x3-2)(x+6)
(x4 - 3)(x4 + 3)
I assume you meant x^4 + 5x^2 +10x + 12. The remainder is 28
sqrt(x4) = x4/2 = x2
264
N = x4 x8 = x4+4 = (x4)2 = N2
x to the fourth (x4)