0
f'(x) = x^(3) / 3
Hence
f(x) = 3x^(2) / 3 +C
f(x) = x^(2) + C ' The '3' cancels out. The 'C' is a constant that comes with antoderivation.
What else can I help you with?
What is the antiderivative of e to the -x?
-e-x + C.
What is the answer to x cubed plus 4x squared minus 9x minus 36 divided by x plus 3?
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
Can anyone of can prove that antiderivative is wrong?
The way to disprove an antiderivative is to simply differentiate the function and see if it matches the integral expression. Remember that an antiderivative expression must include a term often coined "C-" an arbitrary constant. For example, ∫(x^3 +14x)dx= (1/4)X^4+ 7X^2 +C. To verify that this is correct, take the derivative. You get x^3 +14x.
What is the Anti-derivative of -3?
The antiderivative of -3 with respect to x is -3x+C. C being any real number.
Can a function have more than one antiderivative?
yes, look at the function f(x)=3x^2 The antiderivative is x^3+C where C is the constant and is more than one value for C. In fact, 3x^2 will have an infinite number of antiderivatives.
What is the antiderivative of square root of x?
(2/3)*x^(3/2)
What is x cubed minus 27 divided by x minus 3?
24
What is x divided by x cubed?
1/x2
What is the antiderivative of radical 1 plus 3 radical x?
sqrt(1) + 3*sqrt(x) = 1 + 3*x^1/2So the antiderivative is x + [3*x^(3/2)]/(3/2) + c = x + 2*x^(3/2) + c where c is the constant of integration.
What is x cubed minus 11 divided by x plus 3?
14
What is the solution when x cubed -y cubed is divided by x -y?
It is x^2 + xy + y^2
What is X cubed divided by X?
X2 (X squared)
X cubed minus x cubed?
x^3 - x^3 = 0 Remember , whilst 'x' is an unknown value, that unkonwn is a fixed value. As a numerical example 3^(3) - 3^(3) = 27 - 27 = 0 The '3' is 'x' in this case
What is the antiderivative of x to the -1?
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
What is the antiderivative of e to the power of one divided by -x?
Powers of e are simple to integrate. The derivative of eu equals u'eu; inversely, the antiderivative of eu equals eu/u'. Therefore, the antiderivative of e1/-x equals (e1/-x)/{d/dx[1/-x]}. The derivative of 1/-x, which can also be expressed as x-1, equals (-1)x(-1-1) = -x-2 = -1/x2.
What is x cubed divided by x squared plus six?
526
2.5 x 3 cubed?
2.5 x 3 cubed = 2.5 x 27 = 67.5
