we have -3q=5 so dividing both sides of the equation by -3 yields q=-5/3.
To solve the equation ( 11 + 8q = 3q - 19 ), first, isolate the variable ( q ). Subtract ( 3q ) from both sides to get ( 11 + 5q = -19 ). Then, subtract 11 from both sides, resulting in ( 5q = -30 ). Finally, divide by 5 to find ( q = -6 ).
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
q=-6
3
3q+11+8q>99
P = 3a - 3q Add 3q to each side: P + 3q = 3a Double each side: 6a = 2P + 6q
If -3q + 4 = 13 then 3q = -9 : q = -3 If 6q = 13 then q = 13/6 = 2 1/6 The question contains an anomaly and is invalid.
3q = 18 q = 6
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
q=-6
It can be simplified to 30pqr which means the same as the given terms
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
9q2 is the square of 3q - so 3q is the result of dividing 9q2 by 3q.
3q + 5 + 2q + 5 = 65 5q + 10 = 65 5q = 55 q = 11 Check it. 33 + 5 + 22 + 5 = 65 It checks.
3
(p-3q) (p-3q) =p2+3pq+3pq+9q2 =p2+6pq+9a2 this is answer hehehhe (jhaylotte)
steps to solve 4(3q-q): =(4)(3q+-q) =(4)(3q)+(4)(-q) =12q-4 answer: 8q