16 x 1 = 16
sqrt[(16x)4] = (16x)2 = 256x2
The expression (2x) to the fourth power is written as ((2x)^4). To simplify it, you apply the exponent to both the coefficient and the variable: ((2^4)(x^4) = 16x^4). Therefore, (2x) to the fourth power equals (16x^4).
If 2x - 16x - 96 = 0, then: -14x = 96 -7x = 48 x = -48/7 Given the wording of your question though, I would guess that you are actually looking for solutions to this equation: 2x2 - 16x -96 = 0 Which we can solve as follows: 2x2 - 16x - 96 = 0 x2 - 8x - 48 = 0 x2 - 12x + 4x - 48 = 0 x(x - 12) + 4(x - 12) = 0 (x + 4)(x - 12) = 0 So x can be equal to either -4 or 12
8x2 + 16x + 8 = 0
16X - 2Y = 4- 2Y = - 16X + 4Y = 8X - 2---------------m(slope) = 8===========
sqrt[(16x)4] = (16x)2 = 256x2
8-16x-32=0 8=16x-32 2x-4=0 2x=4 x=2
[(-16x)12]1/3 = (-16x)4 = 65536x4
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
If 2x - 16x - 96 = 0, then: -14x = 96 -7x = 48 x = -48/7 Given the wording of your question though, I would guess that you are actually looking for solutions to this equation: 2x2 - 16x -96 = 0 Which we can solve as follows: 2x2 - 16x - 96 = 0 x2 - 8x - 48 = 0 x2 - 12x + 4x - 48 = 0 x(x - 12) + 4(x - 12) = 0 (x + 4)(x - 12) = 0 So x can be equal to either -4 or 12
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.
If your function is 4x^2+16x+16=0 then x=-2, if it is 4x^2-16x+16=0, then x=2
8x2 + 16x + 8 = 0
16x = 4 Divide both sides by 16: x = 4/16 x = 1/4
√(16x) = 4√x = 4x1/2
16X - 2Y = 4- 2Y = - 16X + 4Y = 8X - 2---------------m(slope) = 8===========
To factor the equation ( x^3 + 8x^2 + 16x = 0 ), first, rewrite it as ( x^3 + 8x^2 + 16x + 16 = 16 ). By factoring out the common term ( x ), we get ( x(x^2 + 8x + 16) = 0 ). The quadratic ( x^2 + 8x + 16 ) can be factored as ( (x + 4)^2 ). Therefore, the factored form is ( x(x + 4)^2 = 0 ).