2 + g + 5 = g + 7
What is g + (-5) = 27
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
It is g > -1.
It is: (g-5)(g-9)
(g - 16)(g - 16) or (g - 16)2
2 + g + 5 = g + 7
What is g + (-5) = 27
(g + 5)(g + 2)
If G + 5 = g - 2 then G = g + 3 and g = G - 3
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
It is g > -1.
It is: (g-5)(g-9)
g (x) = -3x+5 -3x= 5 x= -5/3
27-g = 2g+12 -3g = -15 g = 5
f(x) = 3x - 1 so f(-2) = 3*(-2) - 1 = -7 g(x) = - x so g(5) = - 5 Then f(-2) + g(5) = -7 - 5 = -12
If "g" has a value then it would just be 5+(the value) Otherwise it would be 5+g G is a variable and therefor could be anything. You can not solve the equation further. The answer is simply 5+G. If you have a previous declaration that states that G=2, then 5+G would equal 7. In computer programming, equations like this are useful for repetitious calculations. For example, if G is the variable for a score in a game, we would start with G=0 and every time you get a point, the computer would calculate G=G+1. G, currently 0, plus 1, equals 1. If you get another point then G, currently 1, plus 1, equals 2. This can be repeated as needed without changing the equation.