G plus 5 * 16 = G + 80
2 + g + 5 = g + 7
What is g + (-5) = 27
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
It is g > -1.
It is: (g-5)(g-9)
(g - 16)(g - 16) or (g - 16)2
2 + g + 5 = g + 7
What is g + (-5) = 27
(g + 5)(g + 2)
If G + 5 = g - 2 then G = g + 3 and g = G - 3
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
It is g > -1.
It is: (g-5)(g-9)
g (x) = -3x+5 -3x= 5 x= -5/3
27-g = 2g+12 -3g = -15 g = 5
First, substitute the values: ( r = 9 ), ( b = 5 ), and ( g = -6 ). Calculating ( (r + b - g) ) gives ( (9 + 5 - (-6)) = 9 + 5 + 6 = 20 ). Next, calculate ( (b + g) ) as ( (5 + (-6)) = 5 - 6 = -1 ). Finally, multiply the results: ( 20 \times (-1) = -20 ).
f(x) = 3x - 1 so f(-2) = 3*(-2) - 1 = -7 g(x) = - x so g(5) = - 5 Then f(-2) + g(5) = -7 - 5 = -12