x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
5x-4 = 5 ÷ x4 or it can be written as 5/x4.
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
(x-4)(x+5)=
the R is 3
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
It is x4 + 11x3 + 41x2 + 61x + 30.
If x = 4 and y = 2 then 4(5+2) = 28
If you mean -6+4x-5 then the given expression can be simplified to 4x-11 and the unknown variable is x
5x-4 = 5 ÷ x4 or it can be written as 5/x4.
5 X 4 = 20
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
1/4(x5) + 3/5(x4) + 3/4(x5) 5/20 + 12/20 + 15/20 = 32/20 =8/5 OR 1 3/5 (one and three fifths)
(x-4)(x+5)=
1,2,4,5,10,20
x4
2 divided by 5 is 0.4, x4 is 1.6