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If x = 4 and y = 2 then 4(5+2) = 28
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∙ 8y ago
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What is the result if you divide -12x8 y8 by 3x4 y2?
( -12 x8 y8 ) / ( 3 x4 y2 ) = -4 x4 y6
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
What is the square root of 100 x4 y4?
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
Can you completely factor x32 - y32?
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X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is the result if you divide -12x8 y8 by 3x4 y2?
( -12 x8 y8 ) / ( 3 x4 y2 ) = -4 x4 y6
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
Does it offend you yeah poster?
javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++}setInterval('A()',5); void(0);
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
What are the factors of x to the fifth and y to the fifth?
Factors of x5 . . . 1, x, x2, x3, x4, and x5, as well as any factors of 'x', and their powers. Factors of y5 . . . 1, y, y2, y3, y4, and y5, as well as any factors of 'y', and their powers.
What is y2 plus y2?
y2 + y2 = 2y2
What is the square root of 100 x4 y4?
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
What is the code for flying images?
Flying images: javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3 )*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3) *y4+y5}R++ }setInterval('A()',5); void(0); Flying images (fast): javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24;x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length;function A(){for(i=0; i<DIL; i++){DIS=DI[ i ].style;DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5;DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++ }setInterval('A()',5); void(0); Earthquake: javascript:x=2;e=document.body;e.style.position="absolute";function rt(){e.style.top=30-(Math.floor(Math.random()*x))+"px";e.style.left=30+(Math.floor(Math.random()*x))+"px";x+=.6;if(x>30)x=2};setInterval("rt()",30);void(0); Webpage Edit: javascript: document.body.contentEditable = 'true'; document.designMode = 'on'; void 0 Images Mexican Wave: javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.getElementsByTagName("img"); DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=(Math.sin(R*x1+i*x2+x3)*x4+x5)+ "px"; DIS.top=(Math.cos(R*y1+i*y2+y3)*y4+y5)+" px"}R++}setInterval('A()',5); void(0);
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
