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What else can I help you with?
What is the result if you divide -12x8 y8 by 3x4 y2?
( -12 x8 y8 ) / ( 3 x4 y2 ) = -4 x4 y6
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
What is the square root of 100 x4 y4?
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
X2 plus y2 equals 100 what is the lengrth of the circles radius?
X2 + y2 = 100 = r2 r = 10
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is the result if you divide -12x8 y8 by 3x4 y2?
( -12 x8 y8 ) / ( 3 x4 y2 ) = -4 x4 y6
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
Does it offend you yeah poster?
javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++}setInterval('A()',5); void(0);
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
What are the factors of x to the fifth and y to the fifth?
Factors of x5 . . . 1, x, x2, x3, x4, and x5, as well as any factors of 'x', and their powers. Factors of y5 . . . 1, y, y2, y3, y4, and y5, as well as any factors of 'y', and their powers.
What is the square root of 100 x4 y4?
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
What is the code for flying images?
Flying images: javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3 )*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3) *y4+y5}R++ }setInterval('A()',5); void(0); Flying images (fast): javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24;x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length;function A(){for(i=0; i<DIL; i++){DIS=DI[ i ].style;DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5;DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++ }setInterval('A()',5); void(0); Earthquake: javascript:x=2;e=document.body;e.style.position="absolute";function rt(){e.style.top=30-(Math.floor(Math.random()*x))+"px";e.style.left=30+(Math.floor(Math.random()*x))+"px";x+=.6;if(x>30)x=2};setInterval("rt()",30);void(0); Webpage Edit: javascript: document.body.contentEditable = 'true'; document.designMode = 'on'; void 0 Images Mexican Wave: javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.getElementsByTagName("img"); DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=(Math.sin(R*x1+i*x2+x3)*x4+x5)+ "px"; DIS.top=(Math.cos(R*y1+i*y2+y3)*y4+y5)+" px"}R++}setInterval('A()',5); void(0);
How do you make Google go crazy?
first copy this: javascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++}setInterval('A()',5); void(0); then look something on google and paste it on the top bar thingy
How old you have to be on fetch?
hei all of you go to google.com and when you have went go to address on the top and copy this and when you have copied press enterjavascript:R=0; x1=.1; y1=.05; x2=.25; y2=.24; x3=1.6; y3=.24; x4=300; y4=200; x5=300; y5=200; DI=document.images; DIL=DI.length; function A(){for(i=0; i-DIL; i++){DIS=DI[ i ].style; DIS.position='absolute'; DIS.left=Math.sin(R*x1+i*x2+x3)*x4+x5; DIS.top=Math.cos(R*y1+i*y2+y3)*y4+y5}R++}setInterval('A()',5); void(0);
