You have two variables which without further information can not tell you about the other. Without saying what they equal you can't even give possible solutions.
simply add the like terms: 4p -3p +2q -2q = p
4p+7q
16p + 6q - 3p - 8q = (16p - 3p) + (6q - 8q) = 13p -2q
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
3
simply add the like terms: 4p -3p +2q -2q = p
4p+7q
Let f(X)=2X2+6X+3 So f(-p)=f(2q) or 2p2-6p+3=8q2+12q+3 or p2-3p=4q2+6q or p2-4q2=3p+6q or (p+2q)(p-2q)=3(p+2q) so p-2q=3
16p + 6q - 3p - 8q = (16p - 3p) + (6q - 8q) = 13p -2q
Yes. 9p2 + 12pq + 4q2 = (3p + 2q)2
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
It is a string of algebraic terms.
3
3p
3p
-(b + c - p - 2q)(b + c + p + 2q)
3p+52