y=1+log2x
implies
-1=log2x
which can be solved by raising both sides as an exponent of 2 (since the logarithm is base 2).
2-1=2log2x
This finally implies:
1/2=x
For explanations of why this is:
Anything to a negative exponent simply equals that thing to the positive of that exponent under 1
5-1=1/51=1/5
x-2=1/x2
2-3=1/23=1/8
and so 2-1=1/2
Any number raised to a logarithm of the same base as itself will equal the number inside the logarithm.
5log520=20
xlogx2y=2y
eln 7=7
and so 2log2x=x
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
1
2
(3, 1)
x = 1 and y = -2
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
if y = 2x then x = log2 y
1
2
(1, 9)
(3, 1)
x = 1 and y = -2
y=x+1 there for answer is 2
y=10
They are expressions.
1
Y = 2x + 1