0
For positive x, this expression is equal to 1. The integral (anti-derivative) is therefore x + C (where C is the arbitrary integration constant).
For negative x, this expression is equal to -1, and the integral is -x + C.
Wolfram Alpha gives the integral as x times sgn(x), where sgn(x) is the "sign" function.
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How do you take the antiderivative of 1 over x?
The general formula for powers doesn't work in this case, because there will be a zero in the denominator. The antiderivative of 1/x is ln(x), that is, the natural logarithm of x.
What is the antiderivative of x to the 1?
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
What is the absolute value of x?
Abs(x) = x when x >= 0Abs(x) = -x when x < 0.In short, abs(x) is the distance from the origin to x, irrespective of whether it is to the left or right.
What is the domain of f of x equals x over the absolute value of x - 3 then - 1?
2
What is the absolute value of a negative integers?
The absolute value of a number is how many spaces the number is away from 0. So if the number was 32, the absolute value would be 32. And if the number was -54, then the absolute value would be 54. ========== The definition of "absolute value" for a number x (written as |x| ) is: |x| = x for x >0 |x| = 0 for x=0 |x| = -x for x<0
