If
f(x)=1/x
then
F(x)=antiderivative of f(x)=ln(|x|)
(the natural log of the absolute value of x)
There's another way of reading this question. The anti derivative of 1 is x+c. Dividing that by x gives you 1 + c/x
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The antiderivative of x2 + x is 1/3x3 + 1/2x2 + C.
It is x|x|/2 + C
the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x
-4/x2
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