sqrt(X + 1) is also; (X + 1)^1/2 ( add 1 to exponent and multiply by inverse ) 2/3(X +1)^3/2
int(e 3x) = (1/3)e 3x ========
the radical of 3 + the radical of 1/3
3root(6)+5root(2) you really answered it yourself!
first the two numbers have the same radicand which is radical 2 so we just add the numbers before them to become 7 radical 2
radical 3 or 6
sqrt(X + 1) is also; (X + 1)^1/2 ( add 1 to exponent and multiply by inverse ) 2/3(X +1)^3/2
√3 + √3 = 2√3
2 radical 30
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
int(e 3x) = (1/3)e 3x ========
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
4√3 + 7√3 = (4 + 7)(√3) = 11√3
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
1
the radical of 3 + the radical of 1/3