sqrt(1) + 3*sqrt(x) = 1 + 3*x^1/2So the antiderivative is x + [3*x^(3/2)]/(3/2) + c
= x + 2*x^(3/2) + c where c is the constant of integration.
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sqrt(X + 1) is also; (X + 1)^1/2 ( add 1 to exponent and multiply by inverse ) 2/3(X +1)^3/2
int(e 3x) = (1/3)e 3x ========
the radical of 3 + the radical of 1/3
3root(6)+5root(2) you really answered it yourself!
first the two numbers have the same radicand which is radical 2 so we just add the numbers before them to become 7 radical 2