It is |B - C|
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the distance from A to B is 24Km
Let the two points be (a,b) and (c,d). Then the distance between D= sqrt [ (a-c)^2 + (b-d)^2] where ^2 means squared.
The negation of B is not between A and C is = [(A < B < C) OR (C < B < A)] If A, B and C are numbers, then the above can be simplified to (B - A)*(C - B) > 0
Let x = the distance from a to b. Therefore, the distance from b to c = 2x+6 The distance from a to c = 4x + 2 Logically, a to c = a to b + b to c so 4x+2 = x+ 2x+6. Now solve for x and you can find all the distances. Sometimes it really helps to draw a picture and write a statement. Example, let x = the distance from a to b. Good luck.
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..