Q: What is the area and perimeter of a shape that has the sides of 8in 5in 2 in and 3 in?

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The area of a rectangle = length x width = 5 x 8 = 40 square inches.

This would be a square, not a rectangle. In either case to get square value just multiply length times width.

The area is 16.25 units2

It is an isosceles triangle which has two equal sides

Area = 2*5 = 10 square inches

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2 x (5 + 9) = 28 inches perimeter

The perimeter or circumference: 2*pi*5 = 10*pi inches

The area of a rectangle = length x width = 5 x 8 = 40 square inches.

19 in

4+4+6+5 = 19 inches is the perimeter

This would be a square, not a rectangle. In either case to get square value just multiply length times width.

The area is 16.25 units2

It is an isosceles triangle which has two equal sides

Area = 2*5 = 10 square inches

the formular for area of a two dimesional object is: L (length) x W (width) = L x W = A Perimiter is figured out by: (L x 2) + (W x 2)= P So the area will be: 14 x 9 = 126 square feet Perimiter: (14 x 2) + (9 x 2) = 28 + 18 = 46 feet

The area of rectangle is : 63.0

I think it is 26ft 5in