That depends on how many sides the figure has.
For example . . .
-- If it's a triangle, then its area is 27.7 cm2.
-- If it's a square, then its area is 64 cm2.
-- If it's a pentagon (5 sides), then its area is 110.1 cm2.
-- If it's a hexagon (6 sides), then its area is 166.3 cm2.
.
.
etc.
It is: 8*8 = 64 square cm
64cm (8cm x 8 sides = 8 x 8 = 64).
Your square must have sides of 2cm so perimeter is 8cm.
No because it would be an isosceles triangle
A rectangle that is 2cm by 4cm has an area of 8cm. It also has a perimeter of 12cm.
60 cm2
It is: 8*8 = 64 square cm
A triangle with side a: 8, side b: 8, and side c: 8 cm has an area of 27.71 cm2
64cm (8cm x 8 sides = 8 x 8 = 64).
Your square must have sides of 2cm so perimeter is 8cm.
No because it would be an isosceles triangle
The lengths of the sides does not provide enough information to answer the question.
A rectangle that is 2cm by 4cm has an area of 8cm. It also has a perimeter of 12cm.
The area of a square is calculated by squaring the length of one of its sides. In this case, the side length is 8 cm, so the area would be 8 cm x 8 cm = 64 square cm.
P = 48cm
32 cm² = 8cm²/2
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = β[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = β[13(13-11)(13-8)(13-7)] = β[1325*6] = β780 β 27.93 cmΒ².