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Q: Find the area of a square with a diagonal of 8cm?

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The area of a square with 8cm sides is 64

area = 8*5 = 40 square cm

Fred Pythagoras. Each side is the square root of half of 8 squared ie root 32...

A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.

40 cm2

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A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2

Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)

64cm2 !

8cm.

To get the area of a square, you square the length, ie area = LxL

infinitely far

The area of a square with 8cm sides is 64

88cm2, but it's a rectangle, not a square.

8 x 8 = 64cm squared

8cm * 8cm = 8*8 cm2 = 64 cm2

It is: 8*8 = 64 square cm

Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm

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