The area of a square with 8cm sides is 64
area = 8*5 = 40 square cm
Fred Pythagoras. Each side is the square root of half of 8 squared ie root 32...
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
40 cm2
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
To get the area of a square, you square the length, ie area = LxL
8cm.
infinitely far
We know that area of square. = 64 c m 2. Hence area of square.
The area of a square with 8cm sides is 64
8 x 8 = 64cm squared
To find the area of a triangle, you can use the formula: Area = 0.5 * base * height. In this case, the base is 8cm and the height is 4cm. Plugging these values into the formula, the area would be 0.5 * 8cm * 4cm = 16 square centimeters.
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
8cm * 8cm = 8*8 cm2 = 64 cm2
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm