32 cm² = 8cm²/2
The area of a square with 8cm sides is 64
area = 8*5 = 40 square cm
Fred Pythagoras. Each side is the square root of half of 8 squared ie root 32...
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
40 cm2
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
To get the area of a square, you square the length, ie area = LxL
8cm.
infinitely far
The area of a square with 8cm sides is 64
8 x 8 = 64cm squared
88cm2, but it's a rectangle, not a square.
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
8cm * 8cm = 8*8 cm2 = 64 cm2
Divide the perimeter length by 4 ie 8cm and square the result ie 8cm x 8cm = 64sq cm
Firstly you need to work out the length of a side. Using Pythagorean Theorem for a right angled triangle a2+b2=c2 where a = the length, b = height & c = diagonal since c = 8 and a = b are the same 2a2 = 64 a2 = 32 a = 5.657 cm since the area of the square is a2 then area = 32cm2