i need help
lwh=V 8*8*3=192 square centimeters.
Assuming the shape is a 3cm x 8cm rectangle, the area of this shape will be 3 x 8 = 24 cm2 - or 24 square centimetres.
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2
54 cm2
24CM
The area is 12cm2
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
i need help
The lengths of the sides does not provide enough information to answer the question.
The area of rectangle is : 24.0
lwh=V 8*8*3=192 square centimeters.
Assuming the shape is a 3cm x 8cm rectangle, the area of this shape will be 3 x 8 = 24 cm2 - or 24 square centimetres.
The lengths of the sides of any shape, other than a triangle or regular polygon do not provide enough information to calculate the area. In the same way that a square can be flexed into a rhombus and the rhombus can then be flattened so that its area changes, the information given in the question is not adequate.
To find the perimeter of something all you have to do is, MEASURE THE DISTANCE AROUND THE OBJECT, for example if you have a triangle and the left side is 8cm, the right side is 5cm, and the bottom is 3cm, add the three measurements, 8cm + 5cm + 3cm = 16cm
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
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