24CM
The area of rectangle is : 24.0
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
just add them all together. 8+8+3+3 =22 CM
The area of the triangle with these sides is found by Heron's formula, which states that: semiperimeter = (a + b + c) / 2 Area = √(s(s - a)(s - b)(s - c)) Then: semiperimeter = (6 + 8 + 4) / 2 cm = 9 cm Area = √(9(9 - 8)(9 - 6)(9 - 4)) cm² ≈ 11.6 cm²
9
The area is 12cm2
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
i need help
The lengths of the sides does not provide enough information to answer the question.
The area of rectangle is : 24.0
lwh=V 8*8*3=192 square centimeters.
To find the perimeter of a shape, you simply add up the lengths of all its sides. In this case, the perimeter would be 8cm + 6cm + 2cm + 5cm + 3cm + 8cm, which equals 32cm. So, the perimeter of the shape with sides measuring 8cm, 6cm, 2cm, 5cm, 3cm, and 8cm is 32cm.
Assuming the shape is a 3cm x 8cm rectangle, the area of this shape will be 3 x 8 = 24 cm2 - or 24 square centimetres.
To find the perimeter of something all you have to do is, MEASURE THE DISTANCE AROUND THE OBJECT, for example if you have a triangle and the left side is 8cm, the right side is 5cm, and the bottom is 3cm, add the three measurements, 8cm + 5cm + 3cm = 16cm
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
9
just add them all together. 8+8+3+3 =22 CM