The area of Taşkent is 468 square kilometers.
Carpet area is carpet area and retail area is retail area
Area having a common drainage is catchment area, whereas area which is uses that water from common drainage area is command area.
Built up area is the area which has been developed.and floor area is the area which is about to built or about to develope.
First consider triangles ACD and BCD. They share a common base, CD, and their height is the distance between the parallel lines AB and CD. Consequently, area(ACD) = area(BCD) . . . . . . . . eqn 1 But ACD = AOD + OCD and BCD = BOC + OCD So area(ACD) = area(AOD) + area(OCD) and area(BCD) = area(BOC) + area(OCD) Substituting in eqn 1, area(AOD) + area(OCD) = area(BOC) + area(OCD) area(AOD) = area(BOC)
The area of triangle is : 60.0
Since the moon is tidally locked to the earth it's day is the same length as it's period, 27.32 days.
In bisection method an average of two independent variables is taken as next approximation to the solution while in false position method a line that passes through two points obtained by pair of dependent and independent variables is found and where it intersects abissica is takent as next approximation..
"Area" in Afrikaans is "area."
Carpet area is carpet area and retail area is retail area
Area having a common drainage is catchment area, whereas area which is uses that water from common drainage area is command area.
-- Find out the population of the area. -- Find out the area of the area. -- Divide the population by the area. The result is the population density of the area.
Built up area is the area which has been developed.and floor area is the area which is about to built or about to develope.
length x width = area
all you do is find the area of the circle... if you mean find the squares area, find the area of the circle, and then the square's area and subtract the squares area to the circles area
The opposite of a sunken area would be a raised area or an elevated area.
You can convert the built up area into the carpet area by simply covering the area in a carpet.
First consider triangles ACD and BCD. They share a common base, CD, and their height is the distance between the parallel lines AB and CD. Consequently, area(ACD) = area(BCD) . . . . . . . . eqn 1 But ACD = AOD + OCD and BCD = BOC + OCD So area(ACD) = area(AOD) + area(OCD) and area(BCD) = area(BOC) + area(OCD) Substituting in eqn 1, area(AOD) + area(OCD) = area(BOC) + area(OCD) area(AOD) = area(BOC)