Area is found by A=Bh. B is base length,and h is height. A is area. So, to solve this problem, you would say the base length, 6 cm, and the height , 4 cm, and multiply them. 6x4=24. The are of the rectangle would have an area of 24 cm. squared.
I think it's probably 6 times 4 which is 24… I think.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
The length should be 6cm and the width is 4cm.
It does nothing.
A=1/2(b)(h). So A=1/2(6cm)(4cm). A=12cm^2, or 12 squared centimeters.
24 square centimeters
The perimeter of a rectangle is calculated by adding up the lengths of all four sides. In this case, the rectangle has two sides of length 6cm and two sides of length 4cm. Therefore, the perimeter would be 6cm + 6cm + 4cm + 4cm = 20cm.
I think it's probably 6 times 4 which is 24… I think.
If 2 sides of the rectangle are 6cm, then the remaining 2 sides are 4cm. Area = Length x Breadth Breadth = Area / Lenghth 24 = 6 x Breadth Breadth = 24 / 6 = 4
You multiply 6 and 4.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
12cm
The length should be 6cm and the width is 4cm.
22cm
The area of rectangle is : 18.0
6 cm x 4 cm = 24cm2 (length x width = area)
It does nothing.