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What is the area of a rhombus with 5 centimeter diagonals?
The diagonals of a rhombus cannot be the same size.
What is the area of a rhombus with the diagonals of 12 and 5?
area_rhombus = product_of_diagonals / 2 = 12 x 5 / 2 = 30 units2 [replace "units" by your measurement unit, eg cm]
What is the perimeter of a rhombus when one of its diagonals is greater than the other diagonal by 5 cm with an area of 150 square cm showing key aspects of work?
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
What is the area of a rhombus 10 ft by 12 ft?
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
What is the perimeter of a rhombus when one of its diagonals is 7.5cm and has an area of 37.5 square cm?
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
What is the area of a rhombus with 5 centimeter diagonals?
The diagonals of a rhombus cannot be the same size.
What is the area of a rhombus with the diagonals of 12 and 5?
area_rhombus = product_of_diagonals / 2 = 12 x 5 / 2 = 30 units2 [replace "units" by your measurement unit, eg cm]
The diagonals of the rhombus are in the ratio 3 4 the perimeter of the rhombus is 40cm find the lengths of the sides and of the diagonals?
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
What is the length of the sides of a rhombus whose diagonals are 10 and 12 respectively?
The diagonals of a rhombus intersect at 90 degrees therefore it has 4 right angle triangles with sides of 5 and 6 respectively with the hypotenuse being a side of the rhombus. So using Pythagoras' theorem: 52+62 = 61 and the square root of this is the length of each side of the rhombus which is approximately 7.81 units of measurement
What is the area of a rhombus whose diagonals are 10 and 12 inches?
If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case. The area of a right-angled triangle is given by: A = base x height / 2 = 5 inches x 6 inches / 2 = 15 square inches Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by: A = 4 x 15 square inches = 60 square inches
The diagonals of a rhombus are 20 cm and 40 cm compute the sine cosine and tangent of the angles between the diagonals and each side of the rhombus.?
Sine = 1/sqrt(5) or 2/sqrt(5) Cosine = 2/sqrt(5) or 1/sqrt(5) Tangent = 1/2 or 2.
What is the area and perimeter of a rhombus whose diagonals are in lengths of 7.5 cm and 10 cm showing work?
Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm
What is the perimeter of a rhombus when one of its diagonals is greater than the other diagonal by 5 cm with an area of 150 square cm showing key aspects of work?
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
What is the area of a rhombus 10 ft by 12 ft?
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
What is the perimeter of a rhombus when one of its diagonals is 7.5cm and has an area of 37.5 square cm?
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
What are five shapes that have at least 2 right angles?
1 A square 2 A rectangle 3 A right angle trapezoid 4 An irregular pentagon 5 The diagonals of a rhombus 6 The diagonals of a kite
How many diagonals does a pentagon have have?
a pentagon has 5 diagonals i ur gud at maths...
