If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case.
The area of a right-angled triangle is given by:
A = base x height / 2
= 5 inches x 6 inches / 2
= 15 square inches
Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by:
A = 4 x 15 square inches
= 60 square inches
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
60 square units.
Answer63cm2. False
If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.
The area of a rhombus is half the product of the diagonals. A = 1/2bc. The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal. The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height). The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.
Area of the rhombus: 0.5*8*10 = 40 square feet
The diagonals of a rhombus cannot be the same size.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
14*8 = 112 sq cm
It is: 0.5*10*12 = 60 square m
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
Multiply the diagonals and divide by 2
Find the area of a rhombs with diagonals that measure 8 and 10.
Area of rhombus = 0.5 times the product of its diagonals
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.