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What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
A right triangle has a hypotenuse of length 15 and a leg of length 8 What is the area of the triangle?
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
A right triangle has legs 6cm and 8cm How far from the vertex must this triangle be cut by a line parallel to the longer leg so that the area of the smaller right triangle is equal to the area of the?
it is 24in The area of the first triangle is 24 [(6*8)/2]. The area of the smaller triangle is 12 [24/2]. The two legs will have a relationship of [4/3x to x], the same as any right triangle.
What is the area of a right angle triangle when its hypotenuse is 10 cm and its sides are in the ratio of 3 to 4?
The sides are 6 and 8 and so the area is 0.5*6*8 = 24 cm2.
Can the lengths 4 and 8 and 10 make a right triangle?
No
