The answer will depend on how many sides the area has. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
A rectangle with dimensions 3 cm by 2 cm would meet the criteria. The perimeter is calculated as (2(length + width) = 2(3 + 2) = 10) cm, which does not satisfy the requirement. However, a rectangle with dimensions 4 cm by 1 cm has a perimeter of 10 cm and an area of 4 sq cm. A shape like a triangle with a perimeter of 12 cm and an area of 6 sq cm could be a right triangle with sides of 3 cm, 4 cm, and 5 cm.
you need to multiply the sides.
The surface area of a cube with sides of 4 cm is 6*42 square cm = 96 sq cm. The surface area of a cube with sides of 2 units is 6*22 square units = 24 sq units.
24 cm. sq.
A circle with radius 2.326 cm (approx) Various ellipses. A rectangle with sides 1 cm and 17 cm or with 2 cm and 8.5 cm or 3 cm and 5.667 cm etc or many other regular and irregular shapes.
A rectangle with dimensions 3 cm by 2 cm would meet the criteria. The perimeter is calculated as (2(length + width) = 2(3 + 2) = 10) cm, which does not satisfy the requirement. However, a rectangle with dimensions 4 cm by 1 cm has a perimeter of 10 cm and an area of 4 sq cm. A shape like a triangle with a perimeter of 12 cm and an area of 6 sq cm could be a right triangle with sides of 3 cm, 4 cm, and 5 cm.
6 square cm. Could be a rectangle of sides 2cm by 3 cm, or 1 cm by 6 cm etc or a triangle of height 6, base 2, etc etc etc. or a circle, ellipse or even something of irregular shape.
you need to multiply the sides.
A square with a side length of 2 cm has an area of 4 square cm
That depends not only on the shape, but on how large it is. Any type of figure can be scaled so that it has any desired perimeter.Examples:A triangle with sides 1 cm, 2 cm, 6 cmA triangle with sides 1 cm, 2 cm, 5 cmA triangle with sides 2 cm, 3 cm, 4 cmA nonagon (more correctly an enneagon) with all sides 1 cm
To find the area of a trapezoid, you use the formula: Area = (1/2) * (sum of parallel sides) * height. In this case, the sum of the parallel sides is 4 cm + 5 cm = 9 cm. Plugging in the values, we get: Area = (1/2) * 9 cm * 3 cm = 13.5 square cm. Therefore, the area of the trapezoid is 13.5 square cm.
The surface area of a cube with sides of 4 cm is 6*42 square cm = 96 sq cm. The surface area of a cube with sides of 2 units is 6*22 square units = 24 sq units.
24 cm. sq.
4cm2
Assuming that the shape is triangular, the area is approx 1139 cm^2.
2*2 = 4 square cm
Any shape you want as long as the area within its boundary is 6cm2.examples:a triangle of base 6 cm and height 2 cm;a rectangle 2cm by 3 cm;an L shaped hexagon with sides 5cm, 2cm, 1cm, 1cm, 4cm, 1cm;circle of radius approx 1.382 cm;