area = 144 square units perimeter = 48 units
Then its area will only be a quater of once it was.
A square prism is one whose two ends are square and the remaining 4 faces are rectangles.
Thee different rectangles with an area of 12 square units are 3 by 4, 2 by 6 and 1 by 12.
You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.
area = 144 square units perimeter = 48 units
Then its area will only be a quater of once it was.
Do you mean the surface area of the box? If so... What you do is break the surface area into 6 rectangles: Two rectangles have sides of length 6.3 and 12.6 inches. Two rectangles have sides of length 6.3 and 4.2 inches. Two rectangles have sides of length 12.6 and 4.2 inches. Find the area of each of the six rectangles (using the standard formula for the area of a rectangle, A = W x H), and add up all six. The sum of the areas of the six rectangles will be the surface area of the box. Since the lengths of the sides are in inches, the area will already be in square inches, and therefore you don't have to "turn it into square inches".
Rectangles have two dimensions: length and width. Multiply them together and you will get the area in square units.
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A square prism is one whose two ends are square and the remaining 4 faces are rectangles.
An L-shaped area can be divided into two rectangles. The total area is the sum of the areas of the two rectangles.
Thee different rectangles with an area of 12 square units are 3 by 4, 2 by 6 and 1 by 12.
Area of a rectangle in square units = length*width
Rectangles and squares.
There is no standard relationship between perimeter and area. For example, you can have two rectangles that have the same perimeter, but different area.
you can't have circumference with a square. if the have the perimeter(the distance around it) you divide it by four then multiply it by two. this only works with squares, not rectangles.