The area of any triangle is (1/2) x (base) x (height).
Can you take it from there ?
First, always start with the base. To find the base in a pyramid like that, and assuming that it forms a right triangle, you will need to use the Pythagorean Theorem on the right triangle to find the height of the rectangular base. Pythagorean theorem = a2 + b2 = c2.You should get that the height of the base (hypotenuse of the triangle) is 10 feet. It is a multiple of a Pythagorean Triple, so you don't even need to use the Pythagorean theorem. Use A(rectangle) = bh to find the area of the base. So, B (area of base) = 70 ft2.Now, find the perimeter of the base. You should get 34 ft.Now you need to find the Lateral Area. LA (lateral area) = ph (perimeter of Base times the height of overall figure). You can figure out the height by splitting the side in half into two right triangles, and you can solve for the height (one of the sides of the newly formed right triangles) by using the Pythagorean theorem once again. LA = 34 X (6.26). LA = 212.84 ft2.The formula for Surface Area is LA + B. SA (surface area) = 212.84 + 70 = 282.84 ft2.
Draw a line joining the top vertex to the middle of the base. This divides the triangle into two right-angled triangles, which are congruent (both have the same side lengths and angles). Each right-angled triangle has a hypotenuse length of 34 cm (the hypotenuse is the side opposite the right angle). They also have a side which is the height of the triangle, 30 cm. By Pythagoras' theorem, the third side of each right-angled triangle is 16 cm long because 342 - 302 = 1156 - 900 = 256 = 162 The base of the isosceles triangle is twice that, so it's 32 cm long.
SA = 2,884 units2
(180-112)/2=34
A 45 degree right triangle with a base of 16 feet 6 3/4 inches has a hypotenuse of: 23.69 inches.
The area of triangle is : 340.0
Doubling those two dimensions would quadruple the area. So new area = 4*34 cm2 = 136 cm2
First, always start with the base. To find the base in a pyramid like that, and assuming that it forms a right triangle, you will need to use the Pythagorean Theorem on the right triangle to find the height of the rectangular base. Pythagorean theorem = a2 + b2 = c2.You should get that the height of the base (hypotenuse of the triangle) is 10 feet. It is a multiple of a Pythagorean Triple, so you don't even need to use the Pythagorean theorem. Use A(rectangle) = bh to find the area of the base. So, B (area of base) = 70 ft2.Now, find the perimeter of the base. You should get 34 ft.Now you need to find the Lateral Area. LA (lateral area) = ph (perimeter of Base times the height of overall figure). You can figure out the height by splitting the side in half into two right triangles, and you can solve for the height (one of the sides of the newly formed right triangles) by using the Pythagorean theorem once again. LA = 34 X (6.26). LA = 212.84 ft2.The formula for Surface Area is LA + B. SA (surface area) = 212.84 + 70 = 282.84 ft2.
Draw a line joining the top vertex to the middle of the base. This divides the triangle into two right-angled triangles, which are congruent (both have the same side lengths and angles). Each right-angled triangle has a hypotenuse length of 34 cm (the hypotenuse is the side opposite the right angle). They also have a side which is the height of the triangle, 30 cm. By Pythagoras' theorem, the third side of each right-angled triangle is 16 cm long because 342 - 302 = 1156 - 900 = 256 = 162 The base of the isosceles triangle is twice that, so it's 32 cm long.
The length is 32. Since an isosceles triangle is symmetrical, the height divides it into two right triangles. The hypotenuse of one of these triangles is 34, one of the legs is 30 (the height), and the other leg is half of the base, which we'll call x. Using the Pythagorean Theorem, we know x^2+30^2=34^2, or x^2+900=1156. This gives us x^2=256, or x=16 (it could also be -16, but this is absurd because it's a length). We said x was half the base, so the base itself is 2x=2*16=32.
The area is 99.0 square units.
pythagoreon thereom 34sq - 30sq = 256 sqrt = 16 base 16+16 = 32 half length of base = SQR(34^2 - 30^2) =SQR(1156-900) =SQR(256) =16 base length = 2x 16=32
SA = 2,884 units2
(180-112)/2=34
A 45 degree right triangle with a base of 16 feet 6 3/4 inches has a hypotenuse of: 23.69 inches.
It's not a triangular pyramid if it has a square base. Assuming that 34 is the base width, each triangle is 986 square feet. There are four of them, totaling 3944 square feet. The base is also considered a face, although it is unlikely that someone would cover that in marble. That's an additional 1156 square feet for a grand total of 5100 square feet if you choose to include it.
678.909