the area is 8
The area of an octagon that has a side length of 2.45m is about 29m2
A pyramid will have as many triangular faces as the number of sides its base has, plus one in the shape of its base. This means an octagon based pyramid has nine faces (eight triangular ones plus the octagon base).
It has one base and one face.
The area of an octagon which is nine feet on each side equates to 391.1 feet2
To find the area of a shaded region within a regular octagon, first calculate the area of the entire octagon using the formula ( A = 2(1 + \sqrt{2})s^2 ), where ( s ) is the length of a side. Then, determine the area of any non-shaded regions (such as triangles or smaller shapes) within the octagon and calculate their total area. Finally, subtract the area of the non-shaded regions from the total area of the octagon to find the area of the shaded region.
If an octagon has a height of 17' and a base of 13'6" then it is not a regular octagon. In that case, a lot more information is required before its area can be calculated.
If the octagon at the base is regular, the side of the octagon is s and the height of the prism is h, the area of each octagonal base (Ab) is Ab = 2(√2 +1) s2 The perimeter of the octagon is P = 8s Then the surface area of the prism is As = 2 Ab + Ph The volume of the prism is V = Ab h
An octagon is a plane figure. It has eight sides, but no real base.
Calculating the volume (V) of an octagonal prism involves finding the area (A) of the octagon that is an end (or base), and then simply multiplying it by the length (L) of the prism. The area of an octagon with a side of length s is given by this formula: Aoctagon = 2 (1 + sqrt 2) s2 or about 4.8284 s2 If we take that and multiply it by the length of the prism, we should arrive at the volume thus: Voctagonal prism = L x Aoctagon
A regular octagon is formed from 8 isosceles triangles, each having a base length of 'd' (the length of a side of the octagon) and base angles of 67.5°. The height of one triangle is, 1/2d.tan67.5 The area of one triangle is, 1/2(base x height) = 1/2d.1/2d.tan67.5 = 1/4.d2tan67.5 The area of the octagon = 8 x area of one triangle = 2d2tan 67.5 = 4.8284d2. Thus, 4.8284d2 = 43560 : d2 = 9021.5714 : d = 94.982 The perimeter = 8d = 759.86 ft. (2dp). Note : It can be shown that the area, A = d2(2 + 2√2).
An octagon pyramid is more properly called an octagon-based pyramid. It is a 3-dimensional object whose base is an octagon. Attached to each side of the octagon are triangles whose bases are exactly the same lengths as the corresponding sides of the octagon. The "free" vertices of these triangles meet at a point, the apex, in a plane above the base.
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The area of an octagon that has a side length of 2.45m is about 29m2
The area of an octagon with sides of 14 units each is 946.37 units2
A pyramid will have as many triangular faces as the number of sides its base has, plus one in the shape of its base. This means an octagon based pyramid has nine faces (eight triangular ones plus the octagon base).
The same as for any pyramid: calculate the base area, multiply by the (perpendicular) height, divide the result by 3.The base area of a regular octagon (equal sides, equal angles), based on the length of the sides "a", is 2(1 + squareroot(2))a2.
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