Area = 22*9 = 198 square feet Perimeter = 22+22+9+9 = 62 feet
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
6x5
No. Consider two rectangles: 1 x 10 and 4 x 5 The 1 x 10 has a perimeter of 22 and an area of 10 The 4 x 5 has a perimeter of 18 and an area of 20 Smaller perimeter, twice the area.
24
Area = 22*9 = 198 square feet Perimeter = 22+22+9+9 = 62 feet
Multiply for the area, add for the perimeter.
a - 28 p - 22
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
The area of a rectangle is not sufficient to determine its shape and therefore its perimeter. For example, each of the following rectangles has an area of 22 square units. But the perimeter, P, varies considerably. sqrt(22)*sqrt(22) : P = 4*sqrt(22) 2*11 : P = 26 1*22 : P = 46 0.1*220 : P = 440.2 0.01*2200 : P = 4400.02 0.001*22000 : P = 44000.002 As you may begin to see, there is no limit to the perimeter.
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
Yes.Yes.Yes.Yes.
5
6x5
No. Consider two rectangles: 1 x 10 and 4 x 5 The 1 x 10 has a perimeter of 22 and an area of 10 The 4 x 5 has a perimeter of 18 and an area of 20 Smaller perimeter, twice the area.
9X2