It is: 450/5 = 90 km per hour
60+60+60=180 180+20=200
rapitity
We can't calculate that, unless you tell us how the distances on the two roads compared.They're probably equal, but you left out that information when you copied the problem.
Speed = Distance / Time First bus speed = 300 / 7.5 = 40km/h Second bus speed = 450 / 9 = 50km/h So now we can put them in to a ratio as 40:50. This can be simplified by dividing both by 10 so you have 4:5
The average speed for both men (together) is 6.66... (repeating) km per hour.
Speed = distance/time so it is 450/5 = 90 km per hour.
Dividing distance travelled by time taken gives 450/5 = 90 kilometres per hour.
The average speed of the bus is 40 km/h (20 km / 0.5 hours).
450/45 = 10 hours of driving time.
88.514Km/hr or 24.587m/s
The bus' average speed is 34.72 meters per second.
The average speed of the bus is 4.5 miles per hour. This is calculated by dividing the total distance traveled (9 miles) by the total time taken (2 hours).
In 1 hour it travels 60 km Hence In 6 hours it travels 6 x 60 = 360 km
40km/hr
1.4:1 in favor of the train.
a bus travels 300 miles in 6 hours
200 miles in 3 hours 20 minutes.