Q: What is the average of the numbers from 1 to 10?

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To find the mean average of 10 numbers requires the 10 number to be added together which will take 9 additions and then divide by the number of numbers which will take 1 division → 9 additions followed by 1 division, a total of 10 operations are nominally needed to find the mean average of 10 numbers.

Add the numbers then divide the sum by the number of numbers you added e.g. average of 1,2,3,4 four numbers add em up 1+2+3+4 =10 divide the sum by the number of numbers 10/4 average of 1,2,3,4 is 2.5

The sum of the first 10 natural numbers is 51, with an average of 5.1

It average of 2 numbers is 9 then take 9 away from 12, so average of 3 numbers is now 9, with 3 'left over.' The 3 which is 'left over' divides among the three numbers by adding 1 to each of them, raising the new average to 10.

That would be the average of those two numbers.The average of two numbers is half of their sum.1/2 (-10 + 6) = 1/2 (-4) = -2

Related questions

To find the mean average of 10 numbers requires the 10 number to be added together which will take 9 additions and then divide by the number of numbers which will take 1 division → 9 additions followed by 1 division, a total of 10 operations are nominally needed to find the mean average of 10 numbers.

Add the numbers then divide the sum by the number of numbers you added e.g. average of 1,2,3,4 four numbers add em up 1+2+3+4 =10 divide the sum by the number of numbers 10/4 average of 1,2,3,4 is 2.5

Assuming mean average: average = sum/number_of_items → 10 = sum/2 → sum = 10 x 2 = 20 So any two numbers with a sum of 10 have a mean average of 10, eg {5, 15}, {1, 19}, {0, 20}, {-5, 25}, etc. With the median average, for two numbers it is exactly the same as the mean average, so any pair of numbers that sum to 20 will do. With the mode average, only the case of the pair of numbers {10, 10} will suffice.

The average is 9.66... recurring.

The average of a group of numbers is the sum of the numbers divided by the number of numbers. Because this is probably a homework problem, I won't give you the answer, but I can give you some help: #1) What is the sum of 10, 3, 8, 4 and 5? #2) How many numbers do you have? #3) Your answer will be the answer to #1 divided by the answer to #2.

You add the 4 numbers altogether and then divide the sum by 4. Example: 1. there are four numbers: 10, 20, 12, 10 2. Add the numbers: 10+20+12+10= 52 3. Divide the sum by the total amount of numbers which is 4: 52/4 Answer/Average: 13

You add the maximum and minimum values, then divide it by 2. ==================== You can't. Let's say you have three numbers. The maximum is 10, the minimum is 1. If the numbers are 1, 7, 10, the average is (1+7+10)/3 =6. If the numbers are 1, 4, 10, the average is (1+4+10)/3 =5. So two different sets of numbers with the same maximum and minimum have different averages!

It average of 2 numbers is 9 then take 9 away from 12, so average of 3 numbers is now 9, with 3 'left over.' The 3 which is 'left over' divides among the three numbers by adding 1 to each of them, raising the new average to 10.

12

The sum of the first 10 natural numbers is 51, with an average of 5.1

Yes. For example, the average of 9, 10, and 11 is 10. 9 + 10 + 11 = 30 30 / 3 = 10

That would be the average of those two numbers.The average of two numbers is half of their sum.1/2 (-10 + 6) = 1/2 (-4) = -2