The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
-2
If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
Yes, it crosses at (0.23,0) and (1.43,0).
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
-2
If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
If you mean 3x2+4x-2 = 0 then it can be solved by means of the quadratic equation formulla
Yes, it crosses at (0.23,0) and (1.43,0).
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
Twice. Between negative two and negative one.
3x2-y=6 3x2-y=6
3 x 2 = 2y - 20y6 = -18y-0.33333 = y