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The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
-2
If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3
Vertical line of symmetry cuts through x = -4 - (sqrt of 3)
Yes, it crosses at (0.23,0) and (1.43,0).