Q: What is the base of a right triangle with sides 3 4 and 5 cm?

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It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm

Acute.

Draw a line joining the top vertex to the middle of the base. This divides the triangle into two right-angled triangles, which are congruent (both have the same side lengths and angles). Each right-angled triangle has a hypotenuse length of 34 cm (the hypotenuse is the side opposite the right angle). They also have a side which is the height of the triangle, 30 cm. By Pythagoras' theorem, the third side of each right-angled triangle is 16 cm long because 342 - 302 = 1156 - 900 = 256 = 162 The base of the isosceles triangle is twice that, so it's 32 cm long.

To have an altitude of 8 cm it could have a base of 12 cm and two equal sides of 10 cm which would satisfy Pythagoras' theorem because an isosceles triangle is in fact two right angle triangles joined together. Area of a triangle = 1/2*base*height Area = 1/2*12*8 = 48 square cm

To find the area of a triangle, you need the length of the base and the height. If the triangle has a base of 19 cm and a height of 21 cm, the area would be (1/2) * base * height = (1/2) * 19 cm * 21 cm = 199.5 cm^2. To find the perimeter of a triangle, you need to add the lengths of all three sides. Without knowing the lengths of the other sides, the perimeter cannot be determined.

Related questions

It will be a right angle triangle with a base of 3cm, a height of 4cm and a hypotenuse of 5cm

This is a right angle triangle.

If a right triangle has sides of 16Cm and 12Cm, the hypotenuse is: 20 cm

The 1st is a right angle triangle and the 2nd is a scalene triangle.

The two sides are each 3086 centimeters in length. An isosceles triangle has a base and two congruent sides. If the base of an isosceles triangle is 43 cm long and the perimeter of that triangle is 6215 cm, then the length of the two congruent sides is 6215 cm minus 43 cm, or 6172 cm. Each side will be half that, or 6172 cm divided by 2, or 3086 cm.

The area of a right-angled triangle with base 8 cm and hypotenuse 10 cm is: 24 cm2

Acute.

The length of the hypotenuse of a right triangle with a 13 cm base and a 6 cm height is 14.32 cm

The two other sides are 5 cm and 12 cm because they comply with Pythagoras' theorem for a right angle triangle.

Draw a line joining the top vertex to the middle of the base. This divides the triangle into two right-angled triangles, which are congruent (both have the same side lengths and angles). Each right-angled triangle has a hypotenuse length of 34 cm (the hypotenuse is the side opposite the right angle). They also have a side which is the height of the triangle, 30 cm. By Pythagoras' theorem, the third side of each right-angled triangle is 16 cm long because 342 - 302 = 1156 - 900 = 256 = 162 The base of the isosceles triangle is twice that, so it's 32 cm long.

It could be 377.0 cm or 383.3 cm depending on which two adjacent sides.

To have an altitude of 8 cm it could have a base of 12 cm and two equal sides of 10 cm which would satisfy Pythagoras' theorem because an isosceles triangle is in fact two right angle triangles joined together. Area of a triangle = 1/2*base*height Area = 1/2*12*8 = 48 square cm