Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
Lots! As long as half the length of the base times the height is 20...
Yes Example: Rectangle A has an area of 64 cm. and a perimeter of 32 8 cm. by 8 cm. Rectangle B has an area of 64 cm. and a perimeter of 40 4 cm. by 16 cm
volume prism = area base × height = 32 cm² × 7 cm = 224 cm³
There are with infinitely many possible dimensions for triangles with a given area.
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
Lots! As long as half the length of the base times the height is 20...
Yes Example: Rectangle A has an area of 64 cm. and a perimeter of 32 8 cm. by 8 cm. Rectangle B has an area of 64 cm. and a perimeter of 40 4 cm. by 16 cm
It is: 128/4 = 32 and 32*32 = 1024 square cm
volume prism = area base × height = 32 cm² × 7 cm = 224 cm³
There are with infinitely many possible dimensions for triangles with a given area.
No. Base times half the altitude gives the area.
If 160 square cm represents an area of a substance and 32 cm its height, then volume = 160x32 = 5120 cubic cm
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
32 cm2 x 7 cm = 224 cm3.
Area = pi*r2 Area = pi(3.2 cm)2 = 32 cm2 ======
It is: 4*8 = 32 cm