To find triangles with an area of 32 cm, we can use the formula A = 1/2 * base * height. One possible triangle could have a base of 16 cm and a height of 4 cm. Another triangle could have a base of 8 cm and a height of 8 cm. A third triangle could have a base of 4 cm and a height of 16 cm.
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For a right triangle, A = 1/2(b)(h), where (b) is the length of the base of the triangle and (h) is the triangle's height. Just plug in some numbers to find all sorts of solutions for a (right) triangle whose area is 32.
Its other diagonal works out as 32 cm using Pythagoras' theorem It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm Its area is: 0.5*32*24 = 384 square cm Its area is also: 0.5*16*12*4 = 384 square cm
Lots! As long as half the length of the base times the height is 20...
Yes Example: Rectangle A has an area of 64 cm. and a perimeter of 32 8 cm. by 8 cm. Rectangle B has an area of 64 cm. and a perimeter of 40 4 cm. by 16 cm
volume prism = area base × height = 32 cm² × 7 cm = 224 cm³
There are with infinitely many possible dimensions for triangles with a given area.