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How can you find 2x3?
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
What is the f dashed x or deriative of 1 over 2xcubed plus 5?
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
What is 7 plus 2x3?
13
2x3?
6
How do you find the end behavior of 2x5 plus 5x4-2x3-7x2-4x-12?
f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.
How can you find 2x3?
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
Which Best describes the relationship between (x - 2) and the polynomial 2x3 plus x2 - 3?
(x-2) is NOT a factor APEX 2021
2x3 plus 3x5- 3x2 equals?
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
What is the f dashed x or deriative of 1 over 2xcubed plus 5?
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
1x3=2x3?
False
What is 27-2x3?
21
Is 2x3 can be written as 23?
no
What is the factor 2x3-8x2 plus 6x?
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
Factor 4x5 plus 6x3 plus 6x2 plus 9?
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
Multiplies of 6?
1x6 2x3
