General equation of a circle on the Cartesian plane: x^2+y^2+2gx+2fy+c = 0
Points: (2, 2) (1, 1) and (7, -3)
Substitute the above values into the general equation to form simultaneous equations
4g+4f+c = -8
2g+2f+c = -2
14g-6f+c = -58
Solving the simultaneous equations: g = -4, f = 1 and c = 4
Substituting the above values into the general equation: x^2+y^2-8x+2y+4 = 0
Completing the squares: (x-4)^2+(y+1)^2-16-1+4 = 0
So: (x-4)^2+(y+1)^2 = 13
Therefore centre of circle is at (4, -1) and its radius is the square root of 13
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
It works out that the centre of the circle is at (4, -3) on the Cartesian plane and its area is 56.549 square cm rounded up to three decimal places.
An infinite number, all passing through the centre.
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
It is the radius from the centre to the circumference or the diameter passing through the centre to both sides of the circumference
No it is not a mountain. It is an imaginary line passing through the centre of the earth.
It works out that the centre of the circle is at (4, -3) on the Cartesian plane and its area is 56.549 square cm rounded up to three decimal places.
An infinite number, all passing through the centre.
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
optic centre is the geometrical centre of the lens the rays of light passing through this point emerges in the same direction without bending.
optic centre is the geometrical centre of the lens the rays of light passing through this point emerges in the same direction without bending.
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
The diameter of a circle is twice its radius and spans the circle passing through its centre.