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What is the equation of a circle whose centre is at -1 -7 and has a radius of 10 on the Cartesian plane?
The equation of a circle with centre (x0, y0) and radius r is given by: (x - x0)² + (y - y0)² = r² For the circle with centre (-1, -7) and radius 10 this gives: (x - -1) + (y - -7)² = 10² → (x + 1)² + (y + 7)² = 100 This can be expanded and rearranged to give: x² +2x + y² + 14y - 50 = 0
What is the radius for a circle whose equation is x2 plus y2 36?
If that means = 36 then then the radius of the circle is 6 units
What are the center and radius of the circle defined by the equation x2 plus y2-6 plus 8y plus 210?
Without an equality sign it can't be considered to be an equation but in general the equation of a circle whose centre is at (a, b) and radius is r is:- (x-a)^2+(y-b)^2 = r^2
What is the equation of a circle whose center is at the origin and whose radius is 4?
x2 + y2 = 2
What is the equation of a circle whose center is at the origin and radius is 2?
It is x2 + y2 = 4
What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
What is the equation of a circle whose centre is at -1 -7 and has a radius of 10 on the Cartesian plane?
The equation of a circle with centre (x0, y0) and radius r is given by: (x - x0)² + (y - y0)² = r² For the circle with centre (-1, -7) and radius 10 this gives: (x - -1) + (y - -7)² = 10² → (x + 1)² + (y + 7)² = 100 This can be expanded and rearranged to give: x² +2x + y² + 14y - 50 = 0
What is the interior point of a circle?
Any point whose distance from the centre of the circle is smaller than the radius of the circle.
What is the radius for a circle whose equation is x2 plus y2 36?
If that means = 36 then then the radius of the circle is 6 units
What are the center and radius of the circle defined by the equation x2 plus y2-6 plus 8y plus 210?
Without an equality sign it can't be considered to be an equation but in general the equation of a circle whose centre is at (a, b) and radius is r is:- (x-a)^2+(y-b)^2 = r^2
What is the equation of a circle whose centre is at 3 -5 and meets the point of 6 -7 on the Cartesian plane?
Centre of circle: (3, -5) Distance from (3, -5) to (6, -7) is the square root of 13 which is the radius Equation of the circle: (x-3)^2 + (y+5)^2 = 13
What is the equation of a circle whose center is at the origin and whose radius is 4?
x2 + y2 = 2
What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
What is equation of a circle whose center is at the origin?
x2 + y2 = r2, where r is the radius.
What is the equation of a circle whose center is at the origin and radius is 2?
It is x2 + y2 = 4
What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
What is the radius of the circle whose equation is x2 y2 8?
sqrt(8) = 2*sqrt(2) = 2.83
