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What is the equation of a circle whose centre is at -1 -7 and has a radius of 10 on the Cartesian plane?
The equation of a circle with centre (x0, y0) and radius r is given by:
(x - x0)² + (y - y0)² = r²
For the circle with centre (-1, -7) and radius 10 this gives:
(x - -1) + (y - -7)² = 10²
→ (x + 1)² + (y + 7)² = 100
This can be expanded and rearranged to give:
x² +2x + y² + 14y - 50 = 0
What else can I help you with?
What is the centre and radius of a circle that passes through the points of 2 0 and 3 1 and -6 10 on the Cartesian plane?
The equation of the circle works out as: (x+2)^2 + (y-5)^2 = 41 The circle's centre is at: (-2, 5) Its radius is the square root of 41
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What is the centre and radius of a circle passing through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane?
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
What is the radius for a circle with the equation x2 plus y2 equals 9?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
What is the centre and radius of a circle passing through the points of 6 3 and -5 2 and 7 2 on the Cartesian plane?
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
What is the equation of a circle with center (3 8) and a radius of 2?
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
What is the centre and radius of a circle enscribed through the points of 6 2 and 8 -2 and 0 2 on the Cartesian plane?
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
What is the centre and radius of a circle that passes through the points of 2 0 and 3 1 and -6 10 on the Cartesian plane?
The equation of the circle works out as: (x+2)^2 + (y-5)^2 = 41 The circle's centre is at: (-2, 5) Its radius is the square root of 41
What is the equation of a circle whose centre is at 3 -5 and meets the point of 6 -7 on the Cartesian plane?
Centre of circle: (3, -5) Distance from (3, -5) to (6, -7) is the square root of 13 which is the radius Equation of the circle: (x-3)^2 + (y+5)^2 = 13
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What equation represents the graph of a circle?
Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2
What is the centre and radius of a circle passing through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane?
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
What is the radius for a circle with the equation x2 plus y2 equals 9?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
What is the centre and radius of a circle passing through the points of 6 3 and -5 2 and 7 2 on the Cartesian plane?
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
What is the radius of the circle with the equation x² plus y² equals 36?
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
The circle is centered at the point -3 2 and has a radius of length 7 What is its equation?
The equation for a circle, centre (a,b), radius r, is:(x-a)+(y-b)=r2So for a circle, centre (-3,2), r=7(x+3)+(y-2)=49
