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50% chance
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
50% chance
1 out of 100
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
The chance of rolling it each time is (1/6). So the chance of rolling it 4 times in a row is(1/6) x (1/6) x (1/6) x (1/6) = (1/1296) = 0.0007716 = 0.0772 % (rounded)The chance of rolling it each time is the same. It's not affected by what came before,since dice have no memory.
The chance is one in 216 (6^-3).The probability of rolling a five once is 1/6. Rolling a five again, on the same die or another, will still have a 1/6 chance. Therefore, the probability of the event occurring twice is 1/36 (1/6^2). Three times has a probability of 1/216 (1/6^3), and so on. It does not matter what die is used, as long as it has six sides.The probability p of rolling a number x times consecutively on an s sided die isp=s^-x
Depends if the dice is bias then you an not have an answer if it is fair then you times 6 by 3 which = 18 so if you want three different outcomes then 3/18 which is simplified to 1/6 of a chance!
mick jagger
The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.
The chance of rolling a double 6 is 1/6x1/6The chance of getting the 3 times in a row is(1/6x1/6)3 or (1/36)3 which is 1/46,656, a very small number!
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).
Instead of thinking of this as rolling 1 die three times, think of it as rolling 3 dice once. The first die will be something. The 2nd die will have a 1/6 chance of being the same as the first. The 3rd die will have a 1 in 6 chance of being the same as the first. As for the 3rd die matching the 2nd, this gets tricky. There is a 1/6 chance it will be the same as the 2nd, but you must then adjust for the 3rd die being the same as the first and second. Having all three the same would be 1/6 * 1/6 or 1/36. So the probability would be 1/6 + 1/6 - 1/36 or 11/36