0
What else can I help you with?
Z2 plus 9z plus 18?
z2 + 9z + 18 = z2 + 6z + 3z + 18 = z(z+6) + 3(z+6) = (z+6)*(z+3)
If x equals y-3 and y equals z2 what is x terms of z?
x= z2 - 3
What are the rules for multiplying and adding numbers with exponents?
ax * ay = a(x+y) Example: z2 * z3 = z5 (ax)y = axyExample: (z2)3 = z6 ax/ay = a(x-y) Example: z3/z2 = z1 = z
How do you solve this z squared minus 12 plus 36?
z2 - 12 + 36 is the same as z2 + 24. That's a simplification, but not a solution. There's nothing to solve, because the question doesn't give an equation. If z2+24 were equal to something, then we'd have an equation, and we would be thrilled to solve it for the value of 'z'.
How do you factor z squared plus 7z plus 6?
The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)
What is the reciprocal of z2-r2?
0
How do you factor z2 plus 7z?
If you mean how do you factor z2 + 50z + 49, since the coefficient of z2 is 1, you just have to figure out what two numbers when multiplied together give you 49 and when added together give you 50. That's obviously 49 and 1. So... z2 + 50z + 49 = (z + 49)(z + 1)
If x2 is an integer divisible by 3 then x is divisible by 3?
Yes. If x is not divisible by 3 then x leaves a remainder of 1 or 2 when it is divided by 3. That is, x is of the form 3y+z where z = 1 or 2. Then x2 = (3y+z)2 = 9y2 + 6yz + z2 = 3(3y2 + 2yz) + z2 The first part of this expression is clearly a multiple of 3, but z2 is not. Whether z = 1 or 2, z2 leaves a remainder of 1 when divided by 3.
How do you Factor z3 - 2z2 9z - 18?
its either (z2+ 9)(z - 2) , (z2+ 2)(z - 9) , or (z2- 9)(z - 2)
The overall force acting on an object after all the forces are combined is the?
After all forces are summed with vector addition, the result is usually known as the net force (Fn) and can be used in the formula (Fn = ma).
What is the Z2?
Z2 is the name of ping golf clubs knock-off ping called them "ping zing"
Z2 plus 9z plus 18?
z2 + 9z + 18 = z2 + 6z + 3z + 18 = z(z+6) + 3(z+6) = (z+6)*(z+3)
If x equals y-3 and y equals z2 what is x terms of z?
x= z2 - 3
What are protection zones?
z1,z2,
How do you convert Pi-network to T-network?
Any pi network can be transformed to an equivalent T network. This is also known as the Wye-Delta transformation, which is the terminology used in power distribution and electrical engineering. The pi is equivalent to the Delta and the T is equivalent to the Wye (or Star) form. Pi NetworkT Network The impedances of the pi network (Za, Zb, and Zc) can be found from the impedances of the T network with the following equations: Za = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z2 Zb = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z1 Zc = ( (Z1*Z2)+(Z1*Z3)+(Z2*Z3) ) / Z3
How do you muiltiply complex numbers?
If z1=a+ib and z2=c+id then the product z1*z2=(ac-bd)+i(ad+bc)
Which is better z2 or s5?
Sony Xperia Z2 lets you display 4K footage on your 4K TV .Galaxy S5 has fingerprint scanner and heart-rate monitor. micro sd card on Z2 up to 16GO, Galaxy S5 up to 128Go Camera Z2 20.7 megapixel, Camera S5 16 megapixels USB port 2.0 on Z2, USB port 3.0 on S5 No Tuner FM (Radio)on S5 and Yes on Z2 Screen IPS with Triluminos on Z2, Super AMOLED on S5 better if you need big storage then Galaxy S5, other depends on how you want to use your phone then decide one or the other
