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Z2 plus 9z plus 18?
z2 + 9z + 18 = z2 + 6z + 3z + 18 = z(z+6) + 3(z+6) = (z+6)*(z+3)
If x equals y-3 and y equals z2 what is x terms of z?
x= z2 - 3
What are the rules for multiplying and adding numbers with exponents?
ax * ay = a(x+y) Example: z2 * z3 = z5 (ax)y = axyExample: (z2)3 = z6 ax/ay = a(x-y) Example: z3/z2 = z1 = z
How do you solve this z squared minus 12 plus 36?
z2 - 12 + 36 is the same as z2 + 24. That's a simplification, but not a solution. There's nothing to solve, because the question doesn't give an equation. If z2+24 were equal to something, then we'd have an equation, and we would be thrilled to solve it for the value of 'z'.
How do you factor z squared plus 7z plus 6?
The procedure for factoring z2+7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variables). Now, we multiply these two numbers together. 1 x 6 = 6 We need to factors of 6 that when added together equal 7. The factors of 6 are as follows 1 x 6 2 x 3 The first set of factors is the only set that adds up to equal 7. So now we break apart the middle term into 1 and 6, so that it looks like this: z2+z+6z+6 Now we group the expression like this (z2+z)+(6z+6) With the parenthesis like this, we can begin pulling out common factors, leaving the expression looking like this z(z+1)+6(z+1) Because the contents of the sets of parenthesis are the same, we can combine the z and the 6 to get the fully-factored expression (z+6)(z+1)
