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(3 - x)(3 + x)

9 - x2 = (3 + x) (3 - x)

Q: How do you factor 9-x squared?

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(2x+3)(x+3)

(x + 12)(x - 3)

3(x2 + 3x + 1)

it is a combination of perfect squares the square of 9x is squared is +/- 3x, and the square of 4 is +/- 2 so the answer is (3x+2)(3x-2) which is 9xsquared-6x+6x-4 =9xsquared-4

factor out a 3x 3x(x-3)=3x2-9x

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x2-9x can be factored by taking x out of each term x(x-9)

You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.

Type your answer here... 81

(3x-4)(3x+4)

(9x + 8)(9x - 8)

9x2 + 8x - 1 = (9x - 1)(x + 1)

9x squared-15x squared = -6

It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

x2 - 9x + 8 = (x-1)(x-8)

(3x + 8)(3x - 8)

-9(x + 8)

x2-9x+8=0 has two solutions:x = 8x = 1