(2x+3)(x+3)
(x + 12)(x - 3)
3(x2 + 3x + 1)
it is a combination of perfect squares the square of 9x is squared is +/- 3x, and the square of 4 is +/- 2 so the answer is (3x+2)(3x-2) which is 9xsquared-6x+6x-4 =9xsquared-4
factor out a 3x 3x(x-3)=3x2-9x
x2-9x can be factored by taking x out of each term x(x-9)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
Type your answer here... 81
(3x-4)(3x+4)
9x2 + 8x - 1 = (9x - 1)(x + 1)
(9x + 8)(9x - 8)
9x squared-15x squared = -6
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
x2 - 9x + 8 = (x-1)(x-8)
(3x + 8)(3x - 8)
-9(x + 8)
x2-9x+8=0 has two solutions:x = 8x = 1