- 2 - 3i
[ 2 - 3i ] is.
11
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
- 2 - 3i
[ 2 - 3i ] is.
The complex conjugate of 2-3i is 2+3i.
The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.
-2 + 3iThe additive inverse: -(-2 + 3i) = 2 - 3iThe conjugate: -2 - 3i
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
0 + 3i
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
11
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i