-8x-8y=-64 -8y=8x-64 y=-x+8
3x+11+5x=75(add 5x and 3x) 8x+11=75(-11) 8x=64(/ 8) x=8(ANSWER)
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
No.
- 8x + 8x = 0 so question is meaningless.
-8x-8y=-64 -8y=8x-64 y=-x+8
-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8
basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8
This can't be solved. You have two varibles.
2, 4, 6 and 8 respectively
3x+11+5x=75(add 5x and 3x) 8x+11=75(-11) 8x=64(/ 8) x=8(ANSWER)
Y-8x plus 9y equals 10y-8x.
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
Also 64
8x plus 4y equals 5 is 8x + 4y = 5.
8x + 23 + 4x - 7x = 64; Find X To make this easier, add like terms: (8x + 4x - 7x) + 26 = 64 Use the order of operations: (12x - 7x) + 26 = 64 5x + 26 = 64 -26 -26 5x = 38 5 5 Finally: x = 7(3/5)
No.