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Q: What is the cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5.?

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The square root of a perfect square and the cube root of a perfect cube is always an integer. A perfect square is a number multiplied by itself. A perfect cube is a number multiplied by itself twice. Example: 3 x 3 is 9, the square of 3 3 x 3 x 3 is 27, the cube of 3

√8 multiplied by 3√2 = 3.563594873 (when rounded)

0, 1To be both a square and a cube, the number has to be a sixth power. You don't need to calculate though, since 06=0 and 16=1.The next 2 sixth powers are 26=64 and 36=729.

It will be the cube root of 15 which is 2.4662120741

Multiplication

Related questions

The cube root of the square root is the sixth root. The sixth root of 729 = 3

For a number to be both a square and a cube, it would have to be a sixth power. There are three sixth powers less than 100: 0^6 = 0, 1^6 = 1 and 2^6 = 64.

The equation is equivalent to 'x to the power of 4 thirds' times 'x to the power of 2.5'.Multiplyling them together, we simply add the powers, giving 'x to the power of 23/6' or the 'sixth root of x to the power of 23'.

The square root of a perfect square and the cube root of a perfect cube is always an integer. A perfect square is a number multiplied by itself. A perfect cube is a number multiplied by itself twice. Example: 3 x 3 is 9, the square of 3 3 x 3 x 3 is 27, the cube of 3

Sixth powers.

√8 multiplied by 3√2 = 3.563594873 (when rounded)

0, 1To be both a square and a cube, the number has to be a sixth power. You don't need to calculate though, since 06=0 and 16=1.The next 2 sixth powers are 26=64 and 36=729.

8.056... (3 d.p.)

For a number to be a perfect square and a perfect cube, it must be a perfect sixth power. Now 36 = 729 is too small and 56 = 15625 is too large, leaving 46 = 4096 as the answer.

It will be the cube root of 15 which is 2.4662120741

The cube is multiplied by 53 = 125.

multiplication

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