f(x) = 3x4 - 2x2 + 7
f ' (x) = 12x3 - 4x
f ' ' (x) = 36x2 - 4
The derivative, with respect to x, is -x/sqrt(1-x2)
(x2 + 1)(x2 - 2)
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
-16,128
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The derivative, with respect to x, is -x/sqrt(1-x2)
(x2 + 1)(x2 - 2)
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
x^2(1 - x)(1 + x)
-16,128
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The derivative of the moment generating function is the expectation. The variance is the second derivative of the moment generation, E(x^2), minus the expectation squared, (E(x))^2. ie var(x)=E(x^2)-(E(x))^2 :)
3x squared minus 25x minus 28
2x squared minus 4
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
No.
No, unless "a" happens to be equal to 0, or to 1.