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What is the second derivative of 3x to the fourth power minus 2x squared plus 7?
f(x) = 3x4 - 2x2 + 7 The function f'(x) = 12x^(3) - 4x !st Derivative f''(x) = 36x - 4 2nd derivative. The answer!!!!!
What is the factorization of this trinomial 2x2 plus 21x plus 49?
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
What is the discriminant of 2x2 plus 5x plus 4 equals 0?
-7
What is the factorization of 2 times x squared plus 21x plus 49?
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
What is the factorization of x3 plus 2x2 35x?
x3 + 2x2 - 35x = x(x + 7)(x - 5)
What is the second derivative of 3x to the fourth power minus 2x squared plus 7?
f(x) = 3x4 - 2x2 + 7 The function f'(x) = 12x^(3) - 4x !st Derivative f''(x) = 36x - 4 2nd derivative. The answer!!!!!
2x2 - 3x plus 7?
2x2 equals 5
What is the factorization of this trinomial 2x2 plus 21x plus 49?
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
8-2x2 equals x plus 22-7 in ax2 plus bx plus c equals 0 form?
8 - 2x2 = x + 22 - 7Combine like terms on the right side:8 - 2x2 = x + 15Subtract 8 from each side:-2x2 = x + 7Add 2x2 to each side:0 = 2x2 + x + 7
What is the discriminant of 2x2 plus 5x plus 4 equals 0?
-7
What is the factorization of the trinomial below 2x2 plus 21x plus 49?
(2x+7)(x+7)
What is the factorization of 2 times x squared plus 21x plus 49?
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
What is the factorization of x3 plus 2x2 35x?
x3 + 2x2 - 35x = x(x + 7)(x - 5)
2x2 plus 3x - 14?
(2x + 7)(x - 2)
What is 24-2x2 sqared plus 7 squared?
124Type your answer here...
What is the factorization of the trinomial below2x2 plus 21x plus 49?
2x2+21x+49 = (2x+7)(x+7)
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
