I think you mean;
f(x) = 3x^2
d/dx(3x^2)
= 6x
512
a3*a-2 = a(3-2) = a
d/dx(X^4) = 4X^3 ( first derivative ) d/dx(4X^3) = 12X^2 ( second derivative )
Two to the fifth power multiplied by three to the second power equals 288.
To find the derivative of ( \frac{3}{\sqrt{x}} ), we can rewrite it as ( 3x^{-\frac{1}{2}} ). Using the power rule, the derivative is ( -\frac{3}{2} x^{-\frac{3}{2}} ). This can also be expressed as ( -\frac{3}{2\sqrt{x^3}} ).
The rule in differentiating any bracket is: The power of the bracket multiplied by the bracket itself but lowered by one degree, then multiplied by the derivative of whatever inside the bracket. Its easy, just remember it this way. y=(1-x^3)^3 y'= 3(1-x^3)^2(-3x^2)= -9x^2(1-x^3)^2
512
a3*a-2 = a(3-2) = a
Two to the fifth power multiplied by three to the second power equals 288.
d/dx(X^4) = 4X^3 ( first derivative ) d/dx(4X^3) = 12X^2 ( second derivative )
To find the derivative of ( \frac{3}{\sqrt{x}} ), we can rewrite it as ( 3x^{-\frac{1}{2}} ). Using the power rule, the derivative is ( -\frac{3}{2} x^{-\frac{3}{2}} ). This can also be expressed as ( -\frac{3}{2\sqrt{x^3}} ).
a, a^3*a^-2 is a^3+-2 which equals just a
a math question
2^-3 = .125.125 * 2 = .25So the answer is: .25
The derivative of 3cos(x) is -3sin(x). This can be found using the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In this case, the derivative of cos(x) is -sin(x), and when multiplied by the constant 3, we get -3sin(x) as the derivative of 3cos(x).
4
Oh, dude, the third derivative of ln(x) is -2/(x^3). But like, who really needs to know that, right? I mean, unless you're planning on impressing your calculus teacher or something. Just remember, math is like a puzzle, except no one actually wants to put it together.