For example.
d/dx sin^-1 X = 1/sqrt(1 - x^2)
Probably derived from the Pythagorean theorem.
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An arc-hyperbolic function is an inverse hyperbolic function.
It is an inverse function of a derivative, also known as an integral.
The inverse of the natural log function lnx is exA function must be one to one to have an inverse and the log function is.I am not sure if that is what you are asking.The derivative of ex is itself.That is to say if f(x)=ex then f'(x)=exIf you are asking about the derivative of lnx, it is 1/xand if you look at logb x=1/(xlnb)Not sure which one you are looking for.
The formula for the derivative of an inverse (finv)' = 1/(f' o (finv)) allows you get a formula for the derivative of the inverse of any function that you already know the derivative of. For example: What is the derivative of sqrt(x)? You could figure this out using the definition of the derivative, but it is complicated. You already know that the derivative of x2 is 2x. So let f = x2; finv = sqrt(x), f' = 2x. This gives: (sqrt(x))' = 1/(2 sqrt(x)). Now you have derived a "square root rule" with almost no work.
well, the second derivative is the derivative of the first derivative. so, the 2nd derivative of a function's indefinite integral is the derivative of the derivative of the function's indefinite integral. the derivative of a function's indefinite integral is the function, so the 2nd derivative of a function's indefinite integral is the derivative of the function.