An arc-hyperbolic function is an inverse hyperbolic function.
It is an inverse function of a derivative, also known as an integral.
The inverse of the natural log function lnx is exA function must be one to one to have an inverse and the log function is.I am not sure if that is what you are asking.The derivative of ex is itself.That is to say if f(x)=ex then f'(x)=exIf you are asking about the derivative of lnx, it is 1/xand if you look at logb x=1/(xlnb)Not sure which one you are looking for.
The formula for the derivative of an inverse (finv)' = 1/(f' o (finv)) allows you get a formula for the derivative of the inverse of any function that you already know the derivative of. For example: What is the derivative of sqrt(x)? You could figure this out using the definition of the derivative, but it is complicated. You already know that the derivative of x2 is 2x. So let f = x2; finv = sqrt(x), f' = 2x. This gives: (sqrt(x))' = 1/(2 sqrt(x)). Now you have derived a "square root rule" with almost no work.
well, the second derivative is the derivative of the first derivative. so, the 2nd derivative of a function's indefinite integral is the derivative of the derivative of the function's indefinite integral. the derivative of a function's indefinite integral is the function, so the 2nd derivative of a function's indefinite integral is the derivative of the function.
An arc-hyperbolic function is an inverse hyperbolic function.
If f(x)=y, then the inverse function solves for y when x=f(y). You may have to restrict the domain for the inverse function to be a function. Use this concept when finding the inverse of hyperbolic functions.
An arctanh is the inverse hyperbolic tangent function.
An arccosh is the inverse hyperbolic cosine function.
An antihyperbolic function is a mathematical term for an inverse hyperbolic function.
The inverses of hyperbolic function are the area hyperbolic functions. They are called area functions becasue they compute the area of a sector of the unit hyperbola x2 − y2 = 1 This is similar to the inverse trig functions which correspond to arclength of a sector on the unit circle
It is an inverse function of a derivative, also known as an integral.
The inverse of the natural log function lnx is exA function must be one to one to have an inverse and the log function is.I am not sure if that is what you are asking.The derivative of ex is itself.That is to say if f(x)=ex then f'(x)=exIf you are asking about the derivative of lnx, it is 1/xand if you look at logb x=1/(xlnb)Not sure which one you are looking for.
The formula for the derivative of an inverse (finv)' = 1/(f' o (finv)) allows you get a formula for the derivative of the inverse of any function that you already know the derivative of. For example: What is the derivative of sqrt(x)? You could figure this out using the definition of the derivative, but it is complicated. You already know that the derivative of x2 is 2x. So let f = x2; finv = sqrt(x), f' = 2x. This gives: (sqrt(x))' = 1/(2 sqrt(x)). Now you have derived a "square root rule" with almost no work.
no you cant
Placing a question mark at the end of a phrase does not make it a sensible question. Try to use a whole sentence to describe what it is that you want answered.
well, the second derivative is the derivative of the first derivative. so, the 2nd derivative of a function's indefinite integral is the derivative of the derivative of the function's indefinite integral. the derivative of a function's indefinite integral is the function, so the 2nd derivative of a function's indefinite integral is the derivative of the function.