There should not be any y in the derivative itself since y or y(x) is the function whose derivative you are finding.
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
assuming that you are referring to a function: f(y) = y×y or better put: f(y) = y2 Then it's derivative would be: f'(y) = 2y
in respect to y 2y*3-y collecting the three times the coefficient of y which is 2 6y-y 6y-y=5y the derivative of 5y in respect to y is 5.
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
Derivative of e2x - y = 2e2x - dy/dx
There should not be any y in the derivative itself since y or y(x) is the function whose derivative you are finding.
If y = 3x +- 1, the derivative with respect to x is y' = 3.
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
assuming that you are referring to a function: f(y) = y×y or better put: f(y) = y2 Then it's derivative would be: f'(y) = 2y
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
Find the derivative of Y and then divide that by the derivative of A
If y is a function of x, that is y=f(x), then the derivative of x-y is 1-y' or 1-dy/dx (where y' or dy/dx is the differential coefficient of y with respect to x).
The partial derivative in relation to x: dz/dx=-y The partial derivative in relation to y: dz/dy= x If its a equation where a constant 'c' is set equal to the equation c = x - y, the derivative is 0 = 1 - dy/dx, so dy/dx = 1
in respect to y 2y*3-y collecting the three times the coefficient of y which is 2 6y-y 6y-y=5y the derivative of 5y in respect to y is 5.
You have to specify more information than that. If y is an independent variable and you're talking about the derivative with respect to x, it would be 1/y.
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x